Soal Hots 24 kubus dengan volume masing-masing 1 cm³ disusun menjadi balok dengan ukuran 2 cm x 2 cm x 6 cm. Jika seluruhnya dicat, maka tentukan banyaknya kubus yang 2 permukaannya kena cat. (Soal Olimpiade Matematika SD Pekan Kreasi Anak Indonesia Tahun 2018)

In order for a number to be a prime number, it must only be divisible by 1 and itself. Just like any number that is even can be divisible by 2, any number that ends in 0 or 5 can be divisible by 5. So that is why a number that ends in 5 is not prime, because it has another factor other than 1 and itself, and that would be 5. Hope this helped! :D

Answered by TicTacManiac64 | 2024-06-10

The number with 5 in one place are not prime numbers .
Given that, A statement is to justify that **numbers **with a 5 in one place are not prime numbers .
What is a number system?
A number **system **is described as a technique of composing to represent digits. It is the mathematical inscription for describing numbers of a given set by using numbers or other characters in a uniform method. It delivers a special presentation of every **digit **and describes the arithmetic structure .
Here, Since, the property of a **prime number **is it can be divisible by 1 or itself since 5 is a prime number but double digits or further with number 5 on the one place are not the prime number because they will be divided by 5.
Thus, the number with 5 in one place are not prime numbers .
Learn more about the **number system **here:
https://brainly.com/question/22046046
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Answered by priyankapandeyVT | 2024-06-16

Numbers with a 5 in the ones place (other than 5 itself) cannot be prime because they are divisible by 5. A prime number can only be divided by 1 and itself, and having a 5 in the ones place guarantees additional divisors. Thus, only the number 5 is prime in this category; all other numbers with a 5 at the end are not prime.
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Answered by priyankapandeyVT | 2024-09-26

Jawab: 16 kubusPenjelasan dengan langkah-langkah:24 kubus satuan (1×1×1 cm) disusun menjadi balok 2×2×6 cmSeluruh balok dicat dari luarDicari: banyak kubus yang tepat 2 permukaannya kena catLangkah 1: Memahami posisi kubus dalam balokBalok 2×2×6 dapat dibagi menjadi beberapa kategori posisi kubus:1. Kubus pojok (8 kubus): 3 permukaan kena cat2. Kubus rusuk (kubus di tepi tapi bukan pojok): 2 permukaan kena cat 3. Kubus muka (di permukaan tapi bukan di tepi): 1 permukaan kena cat4. Kubus dalam (tidak menyentuh permukaan luar): 0 permukaan kena catLangkah 2: Menghitung kubus pojokBalok memiliki 8 pojok, jadi ada 8 kubus pojok (3 permukaan kena cat).Langkah 3: Menghitung kubus rusuk (2 permukaan kena cat)Untuk balok 2×2×6:- Rusuk panjang (sejajar sumbu 6 cm): 4 rusuk × 4 kubus per rusuk = 16 kubus- Rusuk pendek (sejajar sumbu 2 cm): 8 rusuk × 0 kubus per rusuk = 0 kubusPenjelasan rusuk panjang:- Setiap rusuk panjang memiliki 6 kubus total- Dikurangi 2 kubus pojok = 4 kubus rusuk per rusuk panjang- Ada 4 rusuk panjang dalam balokTotal kubus rusuk = 16 kubusLangkah 4: Verifikasi dengan menghitung semua kategori- Kubus pojok: 8 kubus (3 permukaan kena cat)- Kubus rusuk: 16 kubus (2 permukaan kena cat)- Kubus muka: 0 kubus (1 permukaan kena cat)- Kubus dalam: 0 kubus (0 permukaan kena cat)Total: 8 + 16 + 0 + 0 = 24 kubus Jadi, banyaknya kubus yang tepat 2 permukaannya kena cat adalah 16 kubus.

Answered by zahwa2123 | 2025-07-16