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In Matematika / Sekolah Menengah Atas | 2025-07-15

Sebuah taman berbentuk persegi panjang dengan ukuran panjang 12 m dan lebar 10 m di sekeliling Taman dibuat jalan dengan lebar 1 M luas dari jalan yang dibuat tersebut adalah a.40² b.44² c.48² d.52²

Asked by Harshvardhan4376

Answer (4)

5 2 m ​ = 3 1 ​ ( 2 m − 12 ) 5 2 m ​ = 3 2 ​ m − 3 12 ​ ∣ M u lt i pl y b y 15 6 m = 10 m − 60 ∣ S u b t r a c t 10 m − 4 m = − 60 ∣ D i v i d e b y − 4 m = 15 S o l u t i o n i s m = 15.

Answered by luana | 2024-06-10

2m/5 = 1/3 (2m - 12) First, distribute on the right side of the equal sign.
2m/5 = 1/3 (2m - 12) *** ***
2m/5 = 2/3m -4 Then, get rid of the fraction on the left side of the equal sign, by multiplying the 5 to both sides. Everything on the right side gets multiplied by the five.
2m/5 ·5 ***= 2/3m *** ·5 -4 ·5
2m = 3 1/3 -20 Then, get the variable by itself, by dividing the two on both sides. Everything on the right side gets divided by the two. 2m / 2 = 3 1/3 /2 -20 /2 m = 1 2/3 -10

Answered by xXxGirxXx | 2024-06-10

To solve the equation 5 2 m ​ = 3 1 ​ ( 2 m − 12 ) , first distribute and eliminate fractions by multiplying by 15. Rearranging the equation leads to m = 15 as the solution.
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Answered by luana | 2024-09-27

Jawab:C. 48 m²Penjelasan dengan langkah-langkah:Diketahui :P taman = 12mL taman = 10mP jalan = 12+1+1=14mL jalan = 10+1+1=12mDitanya : L jalan = ?L jalan = L seluruhnya - L taman            = (pxl) - (P taman X L taman)            = (14X12) - (12X10)            = 168 - 120 = 48 m²

Answered by takusahpanggil | 2025-07-16