diketahui kubus ABCD.EFGH dengan panjang rusuk 10 cm .jika titik P terletak pada pertengahan garis GC.jarak C ke bidang BPD adalah.....

42∣2 21∣3 . 7∣7 . 1∣ 42 = 2 × 3 × 7 63∣3 21∣3 . 7∣7 . 1∣ 63 = 3 × 3 × 7

Answered by Anonymous | 2024-06-10

The prime factorization of 42 is 2 multiplied by 3 and 7 (2 × 3 × 7). The prime factorization of 63 is 3 squared multiplied by 7 (3² × 7). Therefore, 42 = 2 × 3 × 7 and 63 = 3² × 7.
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Answered by Anonymous | 2024-10-07

Jawab:Jarak C ke bidang BPD= 5√6 ⁄ 3 cm.Penjelasan dengan langkah-langkah:Hitung Volume Limas P.BCDAlas = ΔBCD (siku‑siku di C)BC = CD = 10 cmL_alas = ½ × BC × CD = ½ × 10 × 10 = 50 cm²Tinggi = PC = ½ × GC = ½ × 10 = 5 cmV = ⅓ × L_alas × Tinggi = ⅓ × 50 × 5 = 250⁄3 cm³Hitung luas segitiga BPDBD = diagonal sisi = 10√2 cmBP = PD = √(BC² + CP²) = √(10² + 5²) = √125 = 5√5 cmTitik O = titik tengah BDCO = ½ × AC = ½ × 10√2 = 5√2 cmPO = √(PC² + CO²) = √(5² + (5√2)²) = √(25 + 50) = √75 = 5√3 cmL_BPD = ½ × BD × PO = ½ × 10√2 × 5√3 = 25√6 cm²Jarak dari C ke bidang BPD (t) V = ⅓ × L_BPD × t 250⁄3 = ⅓ × 25√6 × t 250    = 25√6 × t          t = 250⁄(25√6) = 10⁄√6 = (10√6)⁄6 = (5√6)⁄3 cm

Answered by aekmohop | 2025-07-14