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In Matematika / Sekolah Menengah Atas | 2025-07-14

berapa banyak cara mengurutkan nama 25 orang mahasiswa

Asked by AryaFernandes9530

Answer (3)

a cce l er a t i o n = t im e v e l oc i t y f ina l ​ − v e l oc i t y ini t ia l ​ ​ 20 s 2 m ​ = 22 s v e l oc i t y f ina l ​ − 35 s m ​ ​ ∣ ∗ 22 s 440 s m ​ = v e l oc i t y f ina l ​ − 35 s m ​ ∣ A dd 35 s m ​ v e l oc i t y f ina l ​ = 475 s m ​

Answered by luana | 2024-06-10

The final velocity of the car after accelerating for 22 seconds at 20 m/s², starting from an initial velocity of 35 m/s, is 475 m/s. This is calculated by using the relation between acceleration, initial velocity, and time. Thus, the car speeds up significantly over the period.
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Answered by luana | 2025-06-14

Jawab:25! ≈ 1.55e+25 atau 15.5 kuadriliun triliunPenjelasan dengan langkah-langkah:Jumlah nama mahasiswa: 25Pertanyaan: Berapa banyak cara mengurutkan nama 25 orang mahasiswa?KONSEP:Mengurutkan n objek yang berbeda = n! (n faktorial)Untuk nama 25 mahasiswa: 25!Rumus: n! = n × (n-1) × (n-2) × ... × 2 × 1PERHITUNGAN:25! = 25 × 24 × 23 × ... × 2 × 1Langkah perhitungan:  1! = 1  2! = 2  3! = 6  4! = 24  5! = 120  ....  21! = 51090942171709440000  22! = 1124000727777607680000  23! = 25852016738884976640000  24! = 620448401733239439360000  25! = 15511210043330985984000000

Answered by aekmohop | 2025-07-15