Uang seper tujuh diberikan ke a, 3kali nya diberikan ke b sisa 900

8 × 71 = 568.
The distributive property states that for any real numbers a, b, and c, the following equation holds:
a × (b + c) = a × b + a × c
So, to apply the distributive property to 8×71, we can rewrite it as:
8 × 71 = 8 × (70 + 1)
Now, we can distribute the 8 across the parentheses:
8 × (70 + 1) = (8 × 70) + (8 × 1)
Solving each multiplication, we get:
8×70=560
8×1=8
So, putting it all together:
8×71=(8×70)+(8×1)=560+8=568
Therefore, 8 × 71 = 568.
The probable question maybe:
8 * 71 show multiplication using distributive property.

Answered by nobomika97 | 2024-06-24

Using the distributive property, we can solve 8 × 71 by rewriting it as 8 × (70 + 1). This simplifies to (8 × 70) + (8 × 1) which equals 560 + 8, giving us a final answer of 568.
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Answered by nobomika97 | 2024-09-30

Jawaban:Ringkasan Pertanyaan: Seper tujuh uang diberikan ke A, tiga kali jumlah tersebut diberikan ke B, dan sisanya adalah 900. Berapa jumlah uang semula? Solusi: 1. Misalkan Total Uang:- Misalkan total uang adalah x.2. Uang yang Diberikan ke A:- Uang untuk A = (1/7)x3. Uang yang Diberikan ke B:- Uang untuk B = 3 * (1/7)x = (3/7)x4. Total Uang yang Diberikan ke A dan B:- Total = (1/7)x + (3/7)x = (4/7)x5. Sisa Uang:- Sisa uang = Total uang - Uang yang diberikan- 900 = x - (4/7)x- 900 = (7/7)x - (4/7)x- 900 = (3/7)x6. Cari Total Uang (x):- x = 900 * (7/3)- x = 300 * 7- x = 2100 Jawaban: Jumlah uang semula adalah 2100.

Answered by ara1412 | 2025-08-19