90 – ((36 × 2) : 3) + 15

the midpoint of a line is equal to ( x 2 ​ + x 1 ​ ) /2 and ( y 2 ​ + y 1 ​ ) /2 1 = ( 6 + x 1 ​ ) /2 3.5 = ( − 2 + y 1 ​ ) /2 1 ∗ 2 = 6 + x 1 ​ 3.5 ∗ 2 = − 2 + y 1 ​ 2 − 6 = x 1 ​ 7 + 2 = y 1 ​ − 4 = x 1 ​ 9 = y 1 ​ and thus pont g is at (-4,9)

Answered by publius | 2024-06-10

The coordinates of g are (-4, 9). Since it is given that f(1, 3.5) is the midpoint of gj , these coordinates must lie in between the coordinates of g and j.
How to calculate mid-point when two coordinates are given?
Consider two coordinates as (x1, y1) and (x2, y2)
So, the mid - point is in between those two coordinates. That means it is of the same distance from both coordinates.
∴ mid - point coordinates (x, y) = ( 2 ( x 1 + x 2 ) ​ , 2 ( y 1 + y 2 ) ​ )
Calculation:
The given mid - point is f(1, 3.5)
It is given that coordinates of j(6, -2)
The mid - point lies in between g and j
consider the coordinates of g as (x, y)
So,
(1, 3.5) = ( 2 ( 6 + x ) ​ , 2 ( − 2 + y ) ​ )
On equating ,
1 = (6 + x)/2
⇒ 2 = 6 + x
⇒ x = 2 - 6
∴ x = -4
and
3.5 = (-2 + y)/2
⇒ 3.5 × 2 = -2 + y
⇒ 7 = -2 + y
⇒ y = 7 + 2
∴ y = 9
So, the coordinates of g is ( -4, 9)
Learn more about finding mid - point here:
https://brainly.com/question/13115533
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Answered by tutorconsortium005 | 2024-06-16

The coordinates of point g are (-4, 9) since it lies at the determined position using the midpoint formula based on the given midpoint and endpoint j's coordinates.
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Answered by tutorconsortium005 | 2024-09-17

maaf kalau ada yang salah

Answered by wonuu1996 | 2025-07-15

[tex]90 - ((36 \times 2) \div 3) + 15 \\ = 90 - (72 \div 3) + 15 \\ = 90 - 24 + 15 \\ = 66 + 15 \\ = 81[/tex]

Answered by aquila0152 | 2025-07-16