5 per 16 dikali 8 per 15

In an uniform accelerated motion, the distance covered by the fish is given by: S = 2 1 ​ a t 2 where a is the acceleration t is the time
The acceleration is equal to the increase in speed of the fish divided by the time taken: a = t v f ​ − v i ​ ​ = 0.11 s 4 m / s − 0 m / s ​ = 36.4 m / s 2 If substitute the acceleration into the first equation, we find the distance covered by the fish: S = 2 1 ​ a t 2 = 2 1 ​ ( 36.4 m / s 2 ) ( 0.11 s ) 2 = 0.22 m

Answered by skyluke89 | 2024-06-11

To determine the distance a pike moves during its strike, we use the kinematic equation S = 0.5at^2. Given an acceleration of approximately 36.36 m/s^2 and a time of 0.11 s, the pike moves approximately 0.22 meters during the strike. ;

Answered by BetteDavis | 2024-06-18

The pike accelerates from rest to a speed of 4.0 m/s in 0.11 seconds, resulting in an acceleration of approximately 36.36 m/s². The distance traveled during this acceleration is about 0.22 meters (22.0 cm). Hence, the total distance the pike moves during its strike is 0.22 meters.
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Answered by skyluke89 | 2024-08-28

5/16 x 8/15 = 40/240 = 1/6

Answered by Puzhie | 2025-07-14

[tex] \frac{5}{16} \times \frac{8}{15} \\ \\ = \frac{5 \times 8}{16 \times 15} \\ \\ = \frac{40}{240} = \frac{40 \div 40}{240 \div 40} = \frac{1}{6} [/tex]

Answered by aquila0152 | 2025-07-15