4500 cm=.......dam silahkan jawab pakai cara

Let's solve this problem by working backward from the information given. After 3 p.m., there were 32 geese left on the pond. It was mentioned that thrice the number of geese that flew away at 1 p.m. flew away at 3 p.m., leaving 32 geese. First, let's find the number of geese that flew away at 1 p.m. and worked our way back to the original number.

Let x be the total number of geese originally.
At 1 p.m., 1/5 of the geese flew away, leaving 4/5_x_ geese.
At 2 p.m., 1/8 of the remaining geese flew away, leaving 7/8 of 4/5_x_ geese.
At 3 p.m., three times as many geese as had flown away at 1 p.m. (which is 3 * (1/5_x_)) flew away, leaving 32 geese.

Putting this all together:
4/5_x_ - 1/8(4/5_x_) - 3(1/5_x_) = 32
Solving for x , we find that x = 80.
Therefore, there were 80 geese in the original flock.

Answered by ToddBoyce | 2024-06-24

By solving the problem step-by-step and working backward from the final counts, we discover that the original number of geese in the flock was 80. Each stage of geese flying away leads us to confirm the total estimate consistently matches the data provided. Thus, this final confirmatory measure gives us an accurate original count as per steps followed.
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Answered by ToddBoyce | 2024-09-26

[tex]4.500 \: cm = 4.500 \times \frac{1}{1.000} \: dam[/tex][tex]4.500 \: cm = \frac{4.500}{1.000} \: dam[/tex][tex]4.500 \: cm = \frac{45}{10} \: dam[/tex][tex]4.500 \: cm = 4,5 \: dam[/tex]

Answered by MaulanaAlief | 2025-07-16