{ − 6 x − 4 y = − 14 ∣ ∗ 5 7 x + 5 y = 15 ∣ ∗ 4 { − 30 x − 20 y = − 70 28 x + 20 y = 60 + − − − − − − − 2 x = − 10 ∣ D i v i d e b y − 2 x = 5 5 y = 15 − 7 x 5 y = 15 − 7 ∗ 5 5 y = 15 − 35 5 y = − 20 ∣ : 5 y = − 4 S o l u t i o n i s B ( 5 , − 4 ) .
The solution to the system of equations using elimination is ( 5 , − 4 ) . Thus, the correct answer is Option B. This was found by eliminating one variable and substituting back to find the values for both variables.
;
Un = a + (n - 1) bU11 = 10 + (11 - 1) (-1)U11 = 10 + (10) (-1)U11 = 10 + (-10)U11 = 0