1. Tuliskan network id , host id , dan subnet mask dari ip address berikut ini 120.31.45.19 2. Tuliskan network id , host id , dan subnet mask dari ip address berikut ini 150.70.60.55 Tuliskan network id , host id , dan subnet mask dari ip address berikut ini 192.168.1.1

x 2 + 36 = 12 x x 2 − 12 x + 36 = 0 x 2 − 6 x − 6 x + 36 = 0 x ( x − 6 ) − 6 ( x − 6 ) = 0 ( x − 6 ) ( x − 6 ) = 0 ( x − 6 ) 2 = 0 ⟺ x − 6 = 0 ⇒ x = 6 ​

Answered by Anonymous | 2024-06-10

To solve the equation x 2 + 36 = 12 x , we rearranged it to x 2 − 12 x + 36 = 0 , which factors to ( x − 6 ) 2 = 0 . The solution is x = 6 , and substituting back into the original equation confirms it satisfies the equation.
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Answered by Anonymous | 2024-12-26

Jawaban:IP Address   Kelas   Subnet Mask     Network ID   Host ID  120.31.45.19   A        255.0.0.0           120.0.0.0      31.45.19 50.70.60.55  B        255.255.0.0       150.70.0.0    60.55    192.168.1.1      C        255.255.255.0   192.168.1.0    1        Penjelasan:Class A (1–126.x.x.x)Subnet mask default: 255.0.0.0 (/8)Network ID: octet pertama tetap, sisanya nol.Host ID: tiga octet terakhir.Class B (128–191.x.x.x)Subnet mask default: 255.255.0.0 (/16)Network ID: dua octet pertama tetap, sisanya nol.Host ID: dua octet terakhir.Class C (192–223.x.x.x)Subnet mask default: 255.255.255.0 (/24)Network ID: tiga octet pertama tetap, sisanya nol.Host ID: octet terakhir.

Answered by aekmohop | 2025-07-15