8/15×5/6=tolong bantu jawab
Answer (3)
Hello,
We know that th formula for the area of a rectangle is: A = b ∗ h Now, the problem in this excercise is that there is no restriction on the values that b and h can take, so, they can take any value provided that it meets: b ∗ h = 12 c m 2
for example: l e n g h t = 3 12 c m an d w i d t h = 3 c m A = 3 12 c m ∗ 3 c m A = 12 c m 2
But if they can only take intenger values, what we have to do is to descompose 12, and then we can analyze the possible solutions.
12 | 2 6 | 2 3 | 3 1
12= 2 2 3
first option: 12=4*3
Answer: lenght= 4cm and width= 3cm or vice versa
second option: 12=2*6
**Answer: lenght= 6cm and width= 2cm ** or vice versa
The possible length and width combinations for a rectangle with an area of 12 cm² include: 1 cm x 12 cm, 2 cm x 6 cm, and 3 cm x 4 cm. Each pair gives the same area of 12 cm². The dimensions can also be reversed since length and width can be switched.
;
Penjelasan dengan langkah-langkah:[tex]\tt{} \frac{8}{15} \times \frac{5}{6} [/tex][tex]\tt{} \frac{4}{3} \times \frac{1}{3} [/tex][tex]\tt{} \frac{4 \times 1}{3 \times 3} [/tex][tex]\tt{} \frac{4}{9} [/tex]
