please solve this answer. its about persamaan kuadrat dan tentukan penyelesaiannya dengan pemfaktoran
Answer (4)
3x - 8 = -2 |add 8 to both sides
3x = 6 |divide both sides by 3
x = 2
x - 6 = 2 - 6 = -4
The value of the expression** (x - 6) will be -4.**
What is an Equation?
In mathematics, an equation is a formula that expresses the** equality** of two expressions , by connecting them with the equals sign.
Given is the following **equation **-
3x - 8 = - 2
The given equation is -
3x - 8 = - 2
Solving for** x**, we get -
3x = - 2 + 8
3x = 6
x = 2
Then -
x - 6 will be equal to (2 - 6) or -4.
Therefore, the value of the expression** (x - 6) will be -4.**
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The value of x − 6 is − 4 . This is found by first solving the equation 3 x − 8 = − 2 for x , which gives x = 2 . Subsequently, substituting this value into x − 6 results in − 4 .
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Jawab:x = {0, 5}Penjelasan dengan langkah-langkah:Kita diminta menyelesaikan persamaan:[tex]\displaystyle \frac{6}{x+1} + \frac{4}{x-1} = 2[/tex]dengan syarat:[tex]\begin{aligned}(x+1)(x-1) \neq 0\implies \begin{cases}x + 1 \neq 0 &\Rightarrow x \neq -1\\x - 1 \neq 0 &\Rightarrow x \neq 1\end{cases}\end{aligned}[/tex]Untuk menyelesaikan persamaan tersebut, kita gabungkan dahulu kedua pecahan di sisi kiri. Penyebut bersama/sekutu dari kedua pecahan tersebut adalah (x+1)(x-1), sehingga[tex]\begin{aligned}\frac{6}{x+1} \cdot \frac{x-1}{x-1} + \frac{4}{x-1} \cdot \frac{x+1}{x+1} &= 2 \\\frac{6x-6 + 4x+4}{(x+1)(x-1)} &= \\\frac{10x-2}{(x+1)(x-1)} &= 2 \\10x-2 &= 2(x+1)(x-1)\\10x-2 &= 2x^2-2\\2x^2 -10x &= 0\\2x\left(x-5\right) &= 0\\x &= \begin{cases}x =0\\x = 5\end{cases}\end{aligned}[/tex]Kedua nilai x yang didapat memenuhi syarat (x ≠ 1; x ≠ -1), sehingga kita peroleh himpunan penyelesaiannya adalah x = {0, 5}.Maaf kalau salah, semoga cukup membantu.
