Ada 5 kotak berbentuk kubus ditumpuk. 2 kotak berukuran besar, 3 kotak berukuran kecil. Volume kotak besar 1.728 cm dan kotak keccil 343 cm. Tinggi tumpukan kelima kotak tersebut adalah …cm

The answer is 771/100 or 7 and 71/100 You divide by 1 but to do that, you must move the decimal so that there are only whole numbers, but if you move the decimal, then you have to do the same for 1 but you move it to the right instead of the left=771./100.

Answered by Geekhawk | 2024-06-10

the answer is 711/100 which is an improper fraction.

Answered by MissMexi90210 | 2024-06-10

The decimal 7.71 can be converted to the fraction 100 771 ​ . This is done by separating the whole number from the decimal and converting the decimal part to a fraction. Finally, combine the whole number and the fraction to get the result.
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Answered by Geekhawk | 2024-12-26

Jawaban:45 cmPenjelasan dengan langkah-langkah:Ingat! rumus volume kubus:[tex]volume \: kubus = {s}^{3} [/tex]diket:V kotak besar: 1.728 cmV kotak kecil: 343 cmditanya: tinggi tumpukan...?jawab: [tex]v1 = 1.728 \\ {s}^{3} = 1.728 \\ s = \sqrt[3]{1.728 \\ } \\ s = 12 \: cm\: (tinggi \: kubus \: besar) \\ \\ v2 = 343 \\ {s}^{3} = 343 \\ s = \sqrt[3]{343 \\} \\ s = 7 \: cm \: (tinggi \: kubus \: kecil) \\ \\ tinggi \: tumpukan \: = (12 \times 2) + (7 \times 3) \\ = 24 + 21 \\ = 45 \: cm[/tex]Semoga membantuJadikan jawaban yang tercerdas yaaaaaSemangat belajarnyaaMaaf kalo salah

Answered by fitriaaaa2323 | 2025-07-12