di kelas ada 6 orang yang masuk, jika 6 murid masuk = 100%, maka berapa persen kah apabila yg gamasuk 1 orang

Three unknowns requires three equations to solve . . .

n + d + q = 30
d = 2n
(0.05)n + (0.10)d + (0.25)q = 5.50


plug 2) into 1) and solve for q

n + 2n + q = 30
3n + q = 30
q = 30 - 3n

now we have variables d and q expressed in terms of n, so we plug those equations into 3) and solve for n . . .

0.05n + 0.10(2n) + 0.25(30 - 3n) = 5.50
0.05n + 0.20n + 7.50 - 0.75n = 5.50
(0.05 + 0.20 - 0.75)n + 7.50 = 5.50
-0.50n + 7.50 = 5.50
-0.50n = 5.50 - 7.50
-0.50n = -2.00
n = -2.00/-0.50 = 4
d = 2n = 2(4) = 8
q = 30 - 3n = 30 - 3(4) = 30 - 12 = 18
The answer is . . .
n = 4 nickels d = 8 dimes q = 18 quarters
. . . for a total of (4 + 8 + 18) = 30 coins . . . 8 dimes is twice 4 nickels . . . $0.05(4) + $0.10(8) + $0.25(18) = $5.50

Answered by Anonymous | 2024-06-10

The problem can be solved by creating equations from the facts given: 0.05n + 0.10d + 0.25q = 5.50 and 3n + q = 30. Solving these equations reveals that there are 10 quarters in the collection of coins. ;

Answered by MonteBlue | 2024-06-18

There are 18 quarters in the collection. The solution is based on setting up equations from the given conditions about nickels, dimes, and quarters. By solving these equations step by step, we determine the count of each type of coin.
;

Answered by Anonymous | 2024-12-26

DiketahuiAda 6 OrangDitanyaPresentase yang masuk jika ada 1 orang yang tidak masukDijawabYang masuk[tex] = 6 - 1 \\ = 5[/tex]Presentase[tex] = \frac{5}{6} \times 100\% \\ \\ = 0.83 \times 100\% \\ = 83.3\%[/tex]KesimpulanJadi jawabannya 83,3%

Answered by aquila0152 | 2025-07-11