7 1/9 + 1 11/21 pakai cara. tolong bantu jwb ya kak..

(-2)⁵ = (-2) × (-2) × (-2) × (-2) × (-2) = -32

Answered by Anonymous | 2024-06-10

The value of the expression ( − 2 ) 5 is − 32 . To find this, we multiply − 2 by itself five times, resulting in − 32 .
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Answered by Anonymous | 2024-08-28

Untuk menjumlahkan $$7 \dfrac{1}{9}$$ dan $$1 \dfrac{11}{21}$$, ikuti langkah berikut: 1. Ubah masing-masing pecahan campuran menjadi pecahan biasa (improper fraction):- $$7 \dfrac{1}{9} = \frac{7 \times 9 + 1}{9} = \frac{63 + 1}{9} = \frac{64}{9}$$- $$1 \dfrac{11}{21} = \frac{1 \times 21 + 11}{21} = \frac{21 + 11}{21} = \frac{32}{21}$$ 2. Cari KPK dari penyebut 9 dan 21:- Faktor 9 = $$3^2$$- Faktor 21 = $$3 \times 7$$- KPK = $$3^2 \times 7 = 63$$ 3. Ubah pecahan ke penyebut 63:- $$\frac{64}{9} = \frac{64 \times 7}{9 \times 7} = \frac{448}{63}$$- $$\frac{32}{21} = \frac{32 \times 3}{21 \times 3} = \frac{96}{63}$$ 4. Jumlahkan pecahan:$$\frac{448}{63} + \frac{96}{63} = \frac{544}{63}$$ 5. Ubah kembali ke pecahan campuran:$$544 \div 63 = 8 \text{ sisa } 40$$Jadi,$$\frac{544}{63} = 8 \dfrac{40}{63}$$**Hasil akhir:**$$7 \dfrac{1}{9} + 1 \dfrac{11}{21} = 8 \dfrac{40}{63}$$

Answered by fredojohan94 | 2025-07-14