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There's a quick, easy, sloppy way, and there's a good math way. Here's the good math way:
If the integers are consecutive, then you can call them 'x', (x+1), and (x+2).
We know what their sum is, so let's add them up:
x + (x+1) + (x+2) = 336
x + x+1 + x+2 = 336
Combine the terms that are alike on the left side:
3x + 3 = 336
Subtract 3 from each side: 3x = 333
Divide each side by 3 : x = 111
The integers are*** 111, 112, and 113*** .

Answered by AL2006 | 2024-06-10

To find three consecutive integers that sum to 336, define the first integer as x and the next two as x + 1 and x + 2 . Setting up the equation and solving gives x = 111 , leading to the integers 111, 112, and 113. Thus, the consecutive integers are 111, 112, and 113 .
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Answered by AL2006 | 2024-10-13

Jawaban:6,007,098,240(6 Milyar 7 juta 98 ribu 240)Gunakan cara perkalian biasa, bila perlu gunakan kalkulator!Semoga terbantu!#Math2025

Answered by Dava11072 | 2025-07-13