Acceleration = (change in speed) / (time for the change) = 9/3 = 3 m/s² .
His mass makes no difference.
The student asked about the runner's acceleration when going from 0 m/s to 9 m/s in 3 seconds. To find acceleration, you use the formula:
a = \u2206v / t
where:
a is the acceleration,
\u2206v is the change in velocity (final velocity - initial velocity), and
t is the time over which the change occurs.
In this case:
\u2206v = 9 m/s - 0 m/s = 9 m/s,
t = 3 s.
So the acceleration a is calculated as:
a = 9 m/s / 3 s = 3 m/s2
Therefore, the sprinter's acceleration is 3 meters per second squared.
The sprinter's acceleration is calculated to be 3 m/s², which is found by taking the change in speed (from 0 to 9 m/s) over the time taken (3 seconds). This means the sprinter's speed increases by 3 m/s for each second of acceleration. The mass of the sprinter does not affect this calculation.
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[tex]2 \sqrt{18} - \sqrt{50} + \sqrt{72} [/tex][tex]= 2 \sqrt{9 \times 2} - \sqrt{25 \times 2} + \sqrt{36 \times 2} [/tex][tex]= 2 \times 3 \sqrt{2} - 5 \sqrt{2} + 6 \sqrt{2} [/tex][tex]= 6 \sqrt{2} - 5 \sqrt{2} + 6 \sqrt{2} [/tex][tex]= (6 - 5 + 6) \sqrt{2} [/tex][tex]= 7 \sqrt{2} [/tex]