Here is the solution:
Start with the fact that both trains have made the same distance= 's'.
In physics distance is a multiplication of speed of your train = 'v' and period of time in which it was moving= 'T' (this is only true when the speed doesn't change during movement, or we talk about avarage speed like in your task). Then: s = v D ∗ T D "D" symbol refers do diesel train
Freight train moves with 15[km/h] greater speed and it travels 1 [h] shorter then: s = v F ∗ T F = ( v D + 15 ) ∗ ( T D − 1 )
As the distance made by both train is the same you can compare the right parts of both equations: v D ∗ T D = v F ∗ T F = ( v D + 15 ) ∗ ( T D − 1 )
Diesel train moved 6 hours and freight train 5 hours then: v D ∗ 6 = ( v D + 15 ) ∗ 5 6 ∗ v D = 5 ∗ v D + 75 6 ∗ v D − 5 ∗ v D = 75 v D = 75
Here is your answer: The average diesel train speed is 75 km/h
The average speed of the diesel train is 75 km/h. This is calculated based on the time each train travels and their relative speeds. The freight train, which travels 15 km/h faster, catches up with the diesel train after 5 hours of travel.
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[tex]2.5\% \times 7.000.000 \\ = \frac{2.5}{100} \times 7.000.000 \\ \\ = \frac{17.5 00.000 }{100} = 175.000[/tex]