110 – (25 × 2 : 5) + 6 =

1. − 3 = 12 y − 5 ( 2 y − 7 ) − 3 = 12 y − 10 y + 35 − 3 = 2 y + 35 ∣ S u b t r a c t 35 − 38 = 2 y ∣ D i v i d e b y 2 y = − 19 2. 27 = 3 c − 3 ( 6 − 2 c ) 27 = 3 c − 18 + 6 c 27 = 9 c − 18 ∣ A dd 18 27 + 18 = 9 c 45 = 9 c ∣ D i v i d e b y 9 c = 5

Answered by luana | 2024-06-10

The solutions to the equations are y = − 19 and c = 5 . The first equation simplifies through distribution and combining like terms to find y , while the second also uses distribution and total simplification to solve for c . Both processes involve basic algebraic techniques such as distribution, combining like terms, and isolating variables.
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Answered by luana | 2024-09-05

[tex]110 - (25 \times 2 \div 5) + 6 \\ = 110 - (50 \ \div 5) + 6 \\ = 110 - 10 + 6 \\ = 100 + 6 \\ = 106[/tex]

Answered by aquila0152 | 2025-07-10