∣ A C ∣ = 7 ; ∣ BC ∣ = 5 ∣ A C ∣ = ∣ A B ∣ + ∣ BC ∣ ∣ A B ∣ + 5 = 7 ∣ s u b t r a c t 5 f ro m b o t h s i d es ∣ A B ∣ = 2
A B C The whole segment is AC,AC=7,BC=5. AB=? AC-BC=AB 7-5=2
The length of segment AB is 2 units, calculated using the relationship between the segments AC, AB, and BC. By setting up the equation ∣ A C ∣ = ∣ A B ∣ + ∣ BC ∣ and substituting the values provided, we find ∣ A B ∣ to be 2. Therefore, A B = 2 .
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