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In Matematika / Sekolah Menengah Atas | 2025-07-10

anak kembar kalo satunya lahir tgl 31 desember l, satunya lagi 1 januari itu bedanya setahun,sehari, atau beberapa menit?

Asked by NilamAuliyah9046

Answer (4)

12 − 3 ( 2 w + 1 ) = 7 w − 3 ( 7 + w ) 12 − 6 w − 3 = 7 w − 21 − 3 w 9 − 6 w = 4 w − 21 − 6 w − 4 w = − 21 − 9 − 10 w = − 30 x = − 10 − 30 ​ = 3 ​

Answered by mariamikayla | 2024-06-10

12 − 3 ( 2 w + 1 ) = 7 w − 3 ( 7 + w ) 12 − 6 w − 3 = 7 w − 21 − 3 w − 6 w − 7 w + 3 w = − 21 − 12 + 3 − 10 w = − 30 ∣ D i v i d e d b y − 10 w = 3 Answer is w=3.

Answered by luana | 2024-06-10

The simplified solution for the expression is w = 3 . We expanded and combined like terms on both sides of the equation before isolating w . This process led us to the final answer through systematic simplification.
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Answered by mariamikayla | 2024-10-10

Penjelasan dengan langkah-langkah:beberapa menit, namanya juga anak kembar

Answered by superkittymomochan | 2025-07-13