(…x5)x (1x2)=200 Berapakah angka di titik-titik tersebut 20

S = t d ​ , w h ere s − s p ee d , d − d i s t an ce , t − t im e t = S d ​ d + 37.2 − b e a r d i s t an ce T im e ( t o u r i s t t o u r i s t an d b e a r ) w i ll b e t h e s am e so w e s h o u l d co m p a r i se t h e m : 4 d ​ = 4.96 d + 37.2 ​ 4.96 d = 4 ( d + 37.2 ) 4.96 d = 4 d + 148.8 4.96 d − 4 d = 148.8 0.96 d = 148.8 d = 155 m M a x im u m v a l u e o f d i s 155 m

Answered by luana | 2024-06-10

The maximum possible distance d between the tourist and his car is approximately 155.0 m . This is found by setting the time it takes for both the tourist and the bear to reach the same point equal and solving for d .
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Answered by luana | 2024-09-10

•°• Angka yang tepat untuk mengisi titik-titik pada operasi (... × 5) × (1 × 2) = 200 adalah 20.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:misal, angka yang tidak diketahui → x[tex] \: [/tex](x × 5) × (1 × 2) = 2005x × 2 = 20010x = 200x = 200/10x = 20[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]

Answered by JcyntAvrWiguna | 2025-07-13