(-9/14) : (6/7) =... berapa kak?
Answer (3)
The fewest is two ... one rational and one irrational. They can't be the same number.
The fewest number of distinct points that need to be graphed on a number line for a set that includes both rational and irrational numbers is two: one for a rational number and one for an irrational number. They must not be the same point. For example, one could graph 1 (rational) and 2 (irrational).
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Jawaban:-¾Penjelasan dengan langkah-langkah:[tex] \tt = - \frac{9}{14} \div \frac{6}{7} [/tex][tex] \tt = - \frac{9}{14} \times \frac{7}{6} [/tex][tex] \tt = - \frac{63}{84} [/tex][tex] \tt = - \frac{3}{4} [/tex][tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]
