Sebuah jam dinding berbentuk lingkaran memiliki diameter 30 cm. Keliling jam dinding tersebut adalah .... cm.

3 a x − 5 n ​ = − 4 ∣ A dd 5 n ​ t o b o t h s i d es 3 a x = − 4 + 5 n ​ 3 a x = − 5 20 ​ + 5 n ​ 3 a x = 5 − 20 + n ​ ∣ D i v i d e b y 3 a x = 5 − 20 + n ​ ∗ 3 a 1 ​ x = 15 a − 20 + n ​ A s n w er i s x = 15 a − 20 + n ​ .

Answered by luana | 2024-06-10

The equation given by the student is 3ax - n/5 = -4, and we need to solve for x. To do this, we will perform a series of algebraic steps.
Multiply both sides of the equation by 5 to eliminate the denominator: 5(3ax - n/5) = 5(-4), which simplifies to 15ax - n = -20.
Add n to both sides to isolate terms with x on one side: 15ax = n - 20.
Divide both sides of the equation by 15a to solve for x: x = (n - 20)/(15a).
The solution for x in terms of a and n is x = (n - 20)/(15a).

Answered by qwseagreen | 2024-06-24

The solution for x in the equation 5 3 a x − n ​ = − 4 is x = 3 a − 20 + n ​ . This is found by isolating x through a series of algebraic steps including multiplying, adding, and dividing. The result represents x in terms of a and n .
;

Answered by luana | 2024-10-01

•°• Sebuah jam dinding berbentuk lingkaran memiliki diameter 30 cm. Keliling jam dinding tersebut adalah 94,2 cm.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:diameter jam dinding (d) = 30 cmKeliling jam dinding = ?[tex] \: [/tex]Keliling = πdKeliling = 3,14 × 30Keliling = 94,2 cm[tex] \: [/tex]•°• Jadi, keliling jam dinding tersebut adalah 94,2 cm.[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]

Answered by JcyntAvrWiguna | 2025-07-11

Diketahuid : 30cmDitanyakDijawabKeliling[tex] = \pi \times d \\ = 3.14 \times 30 \\ = 94.2[/tex]KesimpulanJadi jawabannya 94,2cm.

Answered by aquila0152 | 2025-07-11