Asing menurut orang jawa

2w \geq 5\ \ -->w \geq 2,5\\ 2w-5 \leq 5\\ 2w \leq 10\ \ |:2\\ w \leq 5\\\\ Product\ of\ w \leq 5\ and\ w \geq 2,5\\ w\in[2,5;5]"> ∣2 w − 5∣ ≤ 5 F or m u l a f or ab so l u t e v a l u e ∣ a ∣ = a , f or a ≥ 0 or ∣ a ∣ = − a , f or a < 0 1 ) f or 2 w − 5 ≥ 0 − − > 2 w ≥ 5 − − > w ≥ 2 , 5 2 w − 5 ≤ 5 2 w ≤ 10 ∣ : 2 w ≤ 5 P ro d u c t o f w ≤ 5 an d w ≥ 2 , 5 w ∈ [ 2 , 5 ; 5 ] 2w<5--->\ \ w<2,5\\ -2w+5 \leq 5\\ -2w \leq 0\\ w>0\\\\Product\ of\ w>0\ and\ w<2,5\\\\w\in(0;2,5]\\\\ Summing\ both\ cases\ w\in(0,5]"> 2 ) f or 2 w − 5 < 0 − − > 2 w < 5 − − − > w < 2 , 5 − 2 w + 5 ≤ 5 − 2 w ≤ 0 w > 0 P ro d u c t o f w > 0 an d w < 2 , 5 w ∈ ( 0 ; 2 , 5 ] S u mmin g b o t h c a ses w ∈ ( 0 , 5 ]

Answered by luana | 2024-06-10

The solution to the inequality ∣2 w − 5∣ ≤ 5 is w ∈ [ 0 , 5 ] . This means that w can take any value from 0 to 5 inclusive. The solution is derived by breaking down the absolute value inequality into two separate inequalities and solving them respectively.
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Answered by luana | 2024-12-26

Jawaban:Penjelasan:Mereka adalah Malyala (orang Malayala), Aryya (orang dari Arya), Karnnataka (orang dari Karnataka), Cwalika (orang dari Cholika atau Kerajaan ...

Answered by lakshmi12102008 | 2025-07-15