Arranging the following numbers in increasing order (2.3, 45.1, 18.735, 0.9862, 7
) would be:
9862
3
7
735,
1
Take note of the decimal points in which these numbers are associated with however, since these given numbers total varies in interval between each other, this is not directly observed unlike 1.2 1.5 and 1.0
The numbers arranged in increasing order are 0.9862, 2.3, 7, 18.735, and 45.1. We compare the values of each number to determine their positions. This list shows the numbers from smallest to largest clearly.
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Jawab:Penjelasan dengan langkah-langkah:1.[tex]y=x^2[/tex][tex]x=0\to y=0\\y=5\\x^2=5\\x=\pm\sqrt{5}[/tex][tex]L=5\sqrt{5} -\int\limits^{\sqrt{5} }_0 {x^2} \, dx \\L=5\sqrt{5} -\int\limits^{\sqrt{5} }_0 {x^2} \, dx \\L=5\sqrt{5} -\frac{1}{3}x^{3} \,\,|^{\sqrt{5}}_0 \\L=5\sqrt{5} -(\frac{1}{3}(\sqrt{5} )^3 -0)\\L=5\sqrt{5}-\frac{5}{3} \sqrt{5}\\L=\frac{15}{3} \sqrt{5}-\frac{5}{3} \sqrt{5}\\L=\frac{10}{3} \sqrt{5}[/tex]2.[tex]y=4-x^2[/tex][tex]y=0\\4x-x^2=0\\x(4-x)=0\\x=0\text{ atau }x=4[/tex][tex]L=\int\limits^4_0 {4x-x^2} \, dx -\int\limits^8_4 {4x-x^2} \, dx\\L=[2x^2-\frac{1}{3} x^3 ]_0^4-[2x^2-\frac{1}{3} x^3 ]_4^8\\L=((2(4)^2-\frac{1}{3}(4)^3)-(2(0)^2-\frac{1}{3}(0)^3)-((2(8)^2-\frac{1}{3}(8)^3)-(2(4)^2-\frac{1}{3}(4)^3)\\L=(32-\frac{64}{3})-((128-\frac{512}{3})-(32-\frac{64}{3})\\L=2(32-\frac{64}{3})-(128-\frac{512}{3})\\L=64-\frac{128}{3} -128+\frac{512}{3} \\L=-64+\frac{384}{3} \\L=-64+128\\L=64[/tex]3.[tex]y^2=x\\y=\pm\sqrt{x} \\[/tex][tex]x+y=4\\y=4-x[/tex]nilai x pada titik potong kedua kurva di kuadran I:[tex]\sqrt{x} =4-x\\x=4^2-8x+x^2\\x^2-9x+16=0\\x=\frac{9\pm\sqrt{(-9)^2-4(1)(16)} }{2} \\x=\frac{9\pm\sqrt{81-64} }{2} \\x=\frac{9\pm\sqrt{17} }{2}[/tex]karena di kuadran I maka:[tex]x=\frac{9+\sqrt{17} }{2}[/tex]Penyelesaian untuk x tidak sederhana sehingga integrasinya akan panjang sekali. Silakan khusus nomor 3 dibuat pertanyaan terpisah agar saya atau rekan lain bisa membantu.