230.000 - 191.600 = 38.400 itu berapa persen?

74.1% + 25.9% = 100%
we assume 100g of sample
100%-----------100g 25.9% N ------------x x 25.9g N
100g - 25.9g = 74.1g O
mass of N = 14g mass of O = 16g
1 mole of N ------------ 14g x moles of N -------------- 25.9g x = 1.85 moles of N
1 moles of O -------------- 16g x moles of O ----------------- 74.1g x = 4.6 moles of O
N : O = 1.85 : 4.6 we share by the smallest value N : O = 1.85 : 4.6 ||:1.85 N : O = 1 : 2.4 ≈ 1 : 2 NO₂ answer: B

Answered by pyromorphite | 2024-06-10

D.
If we take a sample of 100g of the given compound, we should find that it contains 74.1g of oxygen and 25.9g of nitrogen. The molar masses of oxygen and nitrogen are approximately 16.0g/mol and 14.0g/mol respectively. To find the appropriate number of moles of oxygen and nitrogen found in one mole of the given compound, we divide the mass of the sample by the molar mass of each substance.
For oxygen: 74.1g/(16.0g/mol) = 4.63125 mol (round up to 5 mol)
For nitrogen: 25.9g/(14.0g/mol) = 1.85 mol (round up to 2 mol)
Therefore one mole of this compound contains 2 moles of nitrogen and 5 moles of oxygen.

Answered by Anonymous | 2024-06-10

The molecular formula of the compound made of 25.9% nitrogen and 74.1% oxygen is N₂O₅, corresponding to option d. This was determined by calculating the number of moles for each element and finding their simplest whole number ratio. Thus, the answer is d. N₂O₅.
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Answered by pyromorphite | 2024-12-26

Jawab:Penjelasan dengan langkah-langkah:38.400 jika diubah menjadi persen:38.400 nilainya sama dengan 38.400/1persen adalah bentuk pecahan perseratus yang artinya penyebut (angka bagian bawah diubah terlebih dahulu menjadi 100)38.400/1 = 3.840.000/100= 3.840.000%

Answered by duduali0000 | 2025-07-10