F or m u l a f or a cce l er a t i o n : a = t v 2 − v 1 v 1 = 30 km \hr v 2 = 15 km \hr t = 4 s a = 4 15 − 30 = 4 − 15 = − 3 , 75 s 2 km A cce l er a t i o n i s e q u a l t o 3 , 75 km s 2 . B u s i s d ecce l er a t in g .
Acceleration is the rate of change of speed.
If the speed is increased then its called acceleration
If the speed is decresed then its a negative acceleration also called deceleration
the formula for calculating acceleration is
a = t v − u
where a - acceleration
v - final velocity
u - initial velocity
t - time
v - 15 km/hr should be converted to m/s
distance in 1 hour - 15 km
1 hour = 3600 s
1 km - 1000 m
in 3600 s - 15 000 m
in 1 s - 15 000 m / 3600 s = 4.17 m/s
u - 30 km/hr
in 3600 s - 30 000 m
in 1 s - 30 000 m / 3600 s = 8.33 m/s
substituting the values in the equation
a = 4 s 4.17 m / s − 8.33 m / s = 4 − 4.16 = -1.04 m/s²
the answer is negative means its deceleration
the acceleration is -1.04 m/s²
The acceleration of the bus is calculated to be -1.04 m/s², indicating it is slowing down. This was found by using the formula for acceleration, where the change in velocity, converted to meters per second, was divided by the time interval of 4 seconds. A negative value signifies deceleration.
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Jawaban:150Penjelasan dengan langkah-langkah:Angka Pertama Kelipatan 50Angka Berikutnya Dikurangi 1050 - 10 = 40100 - 10 = 90? - 10 = 140 > ? = 140 + 10 = 150200 - 10 = 190