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In Matematika / Sekolah Menengah Atas | 2025-07-07

3log54-3log4+3log18=..

Asked by notluz3044

Answer (4)

7m+2n=21 -7m -7m
2n = 21-7m
2 2
n= 21-7m 2 10m+4(21-7m/2)= -10 -10m -10m
4(21-7m/2)= -10-10m
(84-28m/2)= -10-10m x2 x2
84-28m = -20-20m +20+28m +20+28m
104 = 8m 8 8
m=13
10(13) + 4n = -10 -130 -130
4n = -140 4 4 n= -35
If anything is unclear please feel free to ask.

Answered by ErzaKirkland | 2024-06-10

The solution for the system of linear equations 7m + 2n = 21 and 10m + 4n = -10 using substitution is m = 5 and n = -9. ;

Answered by BelleX1012 | 2024-06-18

To solve the system of equations, first solve one equation for one variable, then substitute this expression into the second equation. After simplifying, isolate the variable to find its value, and substitute back to find the other variable. The solution is m = 13 and n = − 35 .
;

Answered by BelleX1012 | 2024-12-26

Jawaban:5Penjelasan dengan langkah-langkah:= ³log 54 - ³log 4 + ³log 18[tex] \tt = {}^{3} log(54 \div 4 \times 18) [/tex]= ³log 243= ³log(3⁵)= 5[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]

Answered by Milana01 | 2025-07-07