42 because he won 35 so 5 times 7 equals 35 so you would multiply the other side by seven and 6 times 7 is 42
The question is asking how to determine the total number of games played if a chess player's ratio of wins to losses is 5:6 and the player won 35 games.
We denote the number of wins as ‘5w’ and the number of losses as ’6w’ based on the 5:6 ratio. Knowing that the player won 35 games, we can set ‘5w = 35’, which allows us to solve for ‘w’ by dividing both sides by 5. Therefore, ‘w = 7’. To determine the total games played, we then add the number of wins and losses together, which is ‘5w + 6w = 11w’. Substituting ‘w = 7’ into ‘11w’ gives us a total of 77 games played.
This type of problem often does not have a specific formula, but understanding ratios and simple algebra can help solve it. For example, if the win-loss ratio were different, the same steps could be applied using the new ratio numbers.
The chess player played a total of 77 games. This is calculated by setting the ratio of wins to losses, given as 5:6, and using the known number of wins to find the total number of games played. By solving the equations, we find that the player had 35 wins and 42 losses for a total of 77 games.
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