saat berenang setiap 4 hari sekali,nayu berenang 6 hari sekali,dan dito berenang setiap 9 hari sekali apabila pada tanggal 10 juli 2004 mereka berenang bersama pada tanggal berapa mereka akan berenang bersama lagi
Answer (4)
The buses will meet again at **10:35 am **as determined by finding the least common multiple (LCM) of their routes (25 and 55 minutes), which is 275 minutes (4 hours and 35 minutes) after they leave the bus stop. ;
You have to find the least common multiple (lcm) of 25 and 55.
To find lcm you have to seperate 25 and 55 to prime factors: 25= 5 * 5 55= 5 * 11 Both numbers has one same prime factor which is 5 (bolded). LCM is a multiplication of unique prime factors and one from each pair of the same prime factors, see it below: l c m 25 , 55 = 5 ∗ 5 ∗ 11 = 275
This means that the buses are going to meet at the same stop after 275 minutes from their start. 275 minutes are 4 hours and 35 minutes. Buses start at 6.00 am, add 4 hours and 35 minutes to receive the time of their meeting which is 10.35 am.
The two buses will be at the same stop together next at 10:35 AM after running for 275 minutes, which is 4 hours and 35 minutes from their start time of 6:00 AM.
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Jawaban:15 Agustus 2004Penjelasan dengan langkah-langkah:Faktorisasi prima4 = 2² 6 = 2 × 39 = 3²KPK= 2² × 3²= 4 × 9= 36 hariBersama-sama lagi= 10 Juli 2004 + 36 hari= 15 Agustus 2004
