rata rata nilai kelas A yang berjumlah 12 adalah 8 dan rata rata kelas B yang berjumlah 8 adalah 7 .jika ada satu siswa dari masing masing kelompok dipertukarkan maka rata rata nilai kedua kelas menjadi sama.selisih nilai kedua anak tersebut adalah
Answer (5)
I believe this would be C:
The way I like to think of it is that a direct cause is sorta like something happening on purpose or as expected and an indirect is more unexpected. An easy example might be: Direct: The floor by the elevator was wet so I slipped and fell. Indirect: The floor by the elevator was wet so I took the stairs and fell down them. Hopefully that clarifies the difference.
In the case of C: Jack really slew the giant b/c the giant was after him, but the way this reads he slew the giant b/c of the magic beans, which is really just how he ended up there... kinda like taking the stairs to avoid the elevator. Make sense?
oof its c cuz it is c thats why
The passage that best suggests an indirect cause is C: "Jack slew the giant because he sold the cow for magic beans." This is because it implies a series of events leading to the outcome, rather than a direct cause. The other options either suggest direct causation or do not establish a causal relationship at all.
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Jawaban:20Penjelasan dengan langkah-langkah:12 × 8 - a + b = 8 × 7 - b + a96 - a + b = 56 - b + a-a - a + b + b = 56 - 96-2a + 2b = -40a - b = -40/-2a - b = 20[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]
Jawab:Selisih nilai kedua anak tersebut adalah 4.Penjelasan dengan langkah-langkah:Diketahui:Kelas A:Jumlah siswa = 12Rata-rata = 8Total nilai = 12 × 8 = 96Kelas B:Jumlah siswa = 8Rata-rata = 7Total nilai = 8 × 7 = 56Misalkan:Siswa dari kelas A yang pindah ke B → nilainya = aSiswa dari kelas B yang pindah ke A → nilainya = bSetelah pertukaran:Total nilai baru kelas A:[tex]96 - a + b[/tex]Jumlah siswa tetap = 12Rata-rata baru kelas A:[tex]\frac{96 - a + b}{12}[/tex]Total nilai baru kelas B:[tex]56 - b + a[/tex]Jumlah siswa tetap = 8Rata-rata baru kelas B:[tex]\frac{56 - b + a}{8}[/tex]Samakan kedua rata rata kelas:[tex]\frac{96 - a + b}{12} = \frac{56 - b + a}{8}[/tex]Kalikan silang:[tex]8(96 - a + b) = 12(56 - b + a)[/tex]Bagian kiri:[tex]8(96 - a + b) = 768 - 8a + 8b[/tex]Bagian kanan:[tex]12(56 - b + a) = 672 - 12b + 12a[/tex]Sama dengankan:[tex]768 - 8a + 8b = 672 - 12b + 12a[/tex]Pindahkan semua ke satu sisi:[tex]768 - 8a + 8b - 672 + 12b - 12a = 0[/tex][tex](768 - 672) + (-8a -12a) + (8b + 12b) = 0 \\96 - 20a + 20b = 0[/tex]Bagi semua dengan 20:[tex]- a + b = -4 \Rightarrow b - a = 4[/tex]MakaSelisih nilai kedua anak tersebut adalah 4.
