panjang bidang persegi panjang 15m lebar 10m berapa luas dan kelilingnya
Answer (5)
s = 16 t 2 + 32 t ; s = 161 16 t 2 + 32 t = 161 16 t 2 + 32 t − 161 = 0 a = 16 ; b = 32 ; c = − 161 Δ = b 2 − 4 a c → Δ = 3 2 2 − 4 ⋅ 16 ⋅ ( − 161 ) = 1024 + 10304 = 11328 x 1 = 2 a − b − Δ ; x 2 = 2 a − b + Δ 11328 = 64 ⋅ 177 = 8 177 ≈ 106.4 x 1 = 2 ⋅ 16 − 32 − 106.4 < 0 ; x 2 = 2 ⋅ 16 − 32 + 106.4 = 32 74.4 = 2.325 ≈ 2.3 ( f t )
if I understood correctly: s = 16t^2 + 32t, s=161 16t^2 + 32t=161 16t^2 + 32t-161=0 t=(-32+8√177)/32=-1+√177/4≈2,326≈2,3
The ball takes approximately 2.3 seconds to fall 161 feet. This was calculated by solving the quadratic equation derived from the position equation of the ball. The positive root from the quadratic formula gives us the time of interest.
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•°• Panajng bidang persegi panjang 15 m dan lebarnya 10 m. Luas dan kelilingnya adalah 150 m² dan 50 m.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:panjang (p) = 15 mlebar (l) = 10 mluas dan keliling persegi panjang= ?[tex] \: [/tex]Luas persegi panjang Luas = p × lLuas = 15 m × 10 mLuas = 150 m²[tex] \: [/tex]•°• Jadi, luas persegi panjang tersebut adalah 150 m²[tex] \: [/tex][tex]__________________________________________________________________________________________[/tex]Keliling persegi panjang Keliling = 2(p + l)Keliling = 2(15 m + 10 m)Keliling = 2(25 m)Keliling = 50 m[tex] \: [/tex]•°• Dan, keliling persegi panjang tersebut adalah 50 m.[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
DiketahuiPanjang 15 mLebar 10 mDitanyaLuasKelilingDijawabLuas[tex] = p \times l \\ = 15 \times 10 \\ = {150m}^{2} [/tex]Keliling[tex] = 2 \times (15 + 10) \\ = 2 \times 25 \\ = 50[/tex]KesimpulanMaka luasnya 150m2 dan kelilingnya 50m.
