x- amount of girls y-amount of boys
x+y=51 y+12=2*x
From first equation: x=51-y
substitude to second: y+12=2*(51-y)
y+12=102-2y 3y=102-12
3y=90 /:3 y=30
x=51-30=21
There are 21 girls.
b-boys\\g-girls\\\\ \left\{\begin{array}{ccc}b+g=51\\2g=b+12\end{array}\right\\\\+\left\{\begin{array}{ccc}b+g=51\\2g-b=12\end{array}\right\\----------\\.\ \ \ \ \ \ 3g=63\ \ \ \ /:3\\.\ \ \ \ \ \ g=21\\\\Answer:21\ girls.
There are 21 girls in ninth grade. This was found by defining the relationships between the number of boys and girls in terms of equations. Solving the equations gave us the solution for the number of girls and boys.
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Jawab:satu +9 maka rumus 9:3=3+1jadi nilainya 9+3+3+1=16cm dan 3+1 Penjelasan dengan langkah-langkah:9di bagi 3 jadi 3+1