6 x 2 + x − 2 = 6 x 2 + 4 x − 3 x − 2 = 2 x ( 3 x + 2 ) − 1 ( 3 x + 2 ) = ( 3 x + 2 ) ( 2 x − 1 ) 3 x + 2 = 0 → x = − 3 2 2 x − 1 = 0 → x = 2 1 α = − 3 2 ; β = 2 1 β α + α β = 2 1 − 3 2 + − 3 2 2 1 = − 3 2 ⋅ 1 2 − 2 1 ⋅ 2 3 = − 3 4 − 4 3 = − 12 16 − 12 9 = − 12 25 = − 2 12 1
u se Vi e t a ′ s f or m u l a : β α + α β = α β α 2 + β 2 = α β α 2 + 2 α β + β 2 − 2 α β = α β ( α + β ) 2 − 2 α β = α β ( α + β ) 2 − 2 α + β = a − b ; α β = a c α β ( α + β ) 2 − 2 = a c ( a − b ) 2 − 2 = a 2 b 2 ⋅ c a − 2 = a c b 2 − 2
6 x 2 + x − 2 a = 6 ; b = 1 ; c = − 2 β α + α β = 6 ⋅ ( − 2 ) 1 2 − 2 = − 12 1 − 2 = − 2 12 1
The value of β α + α β for the roots of the polynomial 6 x 2 + x − 2 is − 12 25 . This result is derived using Vieta's formulas and a basic identity involving the squares of the roots. After calculations, the final answer is − 12 25 .
;
Jawaban:he is too poor to buy the house.