Jika x3 - 43 =300 dan y + 5x =42, maka
Answer (4)
The answer on un attached file.
The **length **of the side AB in cm is 9.45.
The **length **of the side **AD **in km is 1.02.
The area of **ΔADC **is 3.56 km².
How to find exterior angle of a triangle ?
The **exterior **angle of a **triangle **is sum of two **opposite **interior angles .
a)
The length of the side AB in cm on the **map **
∠B A C = 55 deg , ∠B C A = 77 deg
∴ ∠**C A B **is
We know the sum of all the interior angles of a triangle is 180 deg
So, ∠B A C + ∠B C A + ∠CAB = 180 deg
55° +77° + ∠CAB = 180 deg
∠C A B = 48 °
∴ sin B** **= 7/AB
sin 48 deg = 7/AB
AB = 7/0.74
AB = 9.45 cm.
b)
The **length **of AD in km is
Again from** interior** angle **theorem ∠ADC **is
= 60 deg
So,sin 60 deg = 7/AD
0.86 = 7/AD
AD = 8.14 cm
∴AD in **km **is 1.02 k m s.
c)
The **area **of **Δ ADC **is
= 1/2 × AC × AD
= 1/2 × 7 × 8.14
= 28.5 cm²
So, the area in km²** **is
= **3.56 **km².
Learn more about **triangles **here :
https://brainly.com/question/16886469
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The length of side AB is approximately 9.23 cm, the length of AD in reality is about 1.18 km, and the area of triangle ΔADC is approximately 0.0003287 km².
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Nilai xx³ - 43 = 300x³ = 300 + 43x³ = 343x = ∛343x = 7Nilai yy + 5x = 427 + 5x = 425x = 42 - 75x = 35x = 7Kesimpulanx = 7y = 7x = y[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]
