\left\{\begin{array}{ccc}ax+by=1&/\cdot a\\bx-ay=a+b&/\cdot b\end{array}\right\\\\+\left\{\begin{array}{ccc}a^2x+aby=a\\b^2x-aby=ab+b^2\end{array}\right\\------------\\.\ \ \ \ \ a^2x+b^2x=a+ab+b^2\\.\ \ \ \ \ \ (a^2+b^2)x=a+ab+b^2\\.\ \ \ \ \ \ \ \ \ \ \ \ x=\frac{a+ab+b^2}{a^2+b^2}\\\\a\cdot\frac{a+ab+b^2}{a^2+b^2}+by=1\\\\\frac{a^2+a^2b+ab^2}{a^2+b^2}+by=1\\\\by=1-\frac{a^2+a^2b+ab^2}{a^2+b^2}
b y = a 2 + b 2 a 2 + b 2 − a 2 + b 2 a 2 + a 2 b + a b 2 b y = a 2 + b 2 a 2 + b 2 − a 2 − a 2 b − a b 2 b y = a 2 + b 2 b 2 − a 2 b − a b 2 y = a 2 b + b 3 b 2 − a 2 b − a b 2
y = b ( a 2 + b 2 ) b ( b − a 2 − ab ) y = a 2 + b 2 b − a 2 − ab A n s w er : x = a 2 + b 2 a + ab + b 2 an d y = a 2 + b 2 b − a 2 − ab
ax+by=1 bx-ay=a+b The solution in attached file
We solved the system of equations by expressing y in terms of x from the first equation and substituting it into the second equation. This allowed us to isolate and solve for x and then substitute back to find y. The final answers for x and y are in terms of constants a and b.
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•°• Jika panjang sebuah tanah adalah 30 m dan lebarnya 30 m, maka luasnya adalah 900 m².[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:panjang tanah (p) = 30 mlebar tanah (l) = 30 mLuas tanah = ?[tex] \: [/tex]Luas = p × lLuas = 30 m × 30 mLuas = 900 m²[tex] \: [/tex]•°• Jadi, luas tanah tersebut adalah 900 m².[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
Diketahuip : 30ml : 30 mDitanyaLuasDijawabLuas[tex] = p \times l \\ = 30 \times 30 \\ = 900 {m}^{2} [/tex]KesimpulanMaka luasnya 900m2.