let three consecutive numbers be a-1 , a ,a+1
sum of above (a-1)+(a)+(a+1) = 237 3a = 237 a = 79
therefore three numbers are = 78, 79,80
Take the three consecutive numbers as x, x+1 and x+2. These three have to add up to 237 so we get the equation:
x + (x+1) + (x+2) = 237 3x + 3 = 237 3x = 234 x = 234 / 3 = 78
Therefore the numbers are x (78), x+1 (79) and x+2 (80)
The three consecutive numbers that add up to 237 are 78, 79, and 80. By letting the first number be x , we derived the equation and solved for x . The solution shows that these numbers add up correctly.
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