a - b = 8 + a + b = 40 2a = 48 a = 24
a - b = 8 24 - b = 8 b = 16
x + y = 40 x − y = 8 − − − − − 2 x = 48 x = 24 24 + y = 40 y = 16
The two numbers that sum to 40 and have a difference of 8 are 24 and 16. This is confirmed by adding and subtracting the numbers. Thus, the numbers are 24 and 16.
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Jawaban:b = 79Penjelasan dengan langkah-langkah:4 × b = 3164b = 316b = 316/4b = 79[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]