0,5 ton + 1 kuintal = … kg
Answer (3)
a 1 = 343 a r = − 1 r = − 7 1 a r = a 1 ∗ q r − 1 − 1 = 343 ∗ q r − 1 − 1 = 343 ∗ − ( 7 1 ) r − 1 − 7 0 = 7 3 ∗ ( − 7 ) − r + 1 7 0 = 7 3 ∗ 7 − r + 1 in d e x es : 0 = 3 − r + 1 = 4 S r = a 1 1 − r 1 − r n S r = 343 ∗ 1 − ( − 7 1 ) 1 − ( − 7 1 ) 4 S r = 343 ∗ 1 + ( 7 1 ) 1 − ( 2401 1 ) S r = 343 ∗ ( 7 8 ) ( 2401 2400 ) S r = 343 ∗ 343 300 S r = 300
S = a 1 ∗ 1 − r 1 − r 2 S = 80 ∗ 1 + 2 1 1 − ( − 2 1 ) 2 S = 80 ∗ 2 3 1 − 4 1 = 80 ∗ 4 3 ∗ 3 2 = 40 3) we dont know how many numbers has this sequence
The sums of the geometric series are as follows: the first series sums to 300, the second series sums to 40, and the third series sums to 765.
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0,5 ton = 500 kg1 kuintal = 100 kgjadi:0,5 ton + 1 kuintal = 500 kg + 100 kg = 600 kg
