x 2 + 12 = 7 ∗ x , where x is unknown numer
Now we are moving 7 ∗ x on left side to obtain quadratic equation:
x 2 + 12 − 7 ∗ x = 0
Our goal is to find two roots of this equation.
First we are finding delta:
Δ = b 2 − 4 ∗ a ∗ c
Δ = ( − 7 ) 2 − 4 ∗ 1 ∗ 12 = 1
First root:
x 1 = 2 ∗ a − b + Δ
x 1 = 2 7 + 1 = 4
Second root:
x 2 = 2 ∗ a − b − Δ
x 2 = 2 7 − 1 = 3
x 2 + 12 = 7 x x 2 − 7 x + 12 = 0 x 2 − 3 x − 4 x + 12 = 0 x ( x − 3 ) − 4 ( x − 3 ) = 0 ( x − 4 ) ( x − 3 ) = 0 x = 4 ∨ x = 3
The numbers that satisfy the condition given in the question are 4 and 3. Both values, when substituted back into the equation, confirm the validity of each solution. Thus, the solutions are correct.
;
Jawaban:= 0,3/100 × 9.000.000= 0,003 × 9.000.000= 27.000