x=44-y} \atop {3*x+5*y=168}\ \ \ \ \ \ \ \ \ \ } \right. \\\\ Substitution\ method\ \\\\3(44-y)+5y=168\\\\132-3y+5y=168\\\\2y=168-132\\\\2y=36 \ \ |:2\\\y=18\\\x=44-y=44-18=26\\\\There \ were\ 26\ children."> x − c hi l d re n y − a d u lt s { 3 ∗ x + 5 ∗ y = 168 x + y = 44 − − > x = 44 − y S u b s t i t u t i o n m e t h o d 3 ( 44 − y ) + 5 y = 168 132 − 3 y + 5 y = 168 2 y = 168 − 132 2 y = 36 ∣ : 2 \y = 18 \x = 44 − y = 44 − 18 = 26 T h ere w ere 26 c hi l d re n .
The Cobb family had 44 people at their reunion, and after setting up equations based on adult and child admissions, we found that there were 26 children at the event. The calculations involved solving a system of equations. This led us to determine that there were also 18 adults present.
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•°• Hasil dari (3/4 + 1/2) × 2 adalah 2 1/2.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:(3/4 + 1/2) × 2= (3/4 + 2/4) × 2= 5/4 × 2= 10/4= 5/2= 2 1/2[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
[tex]( \frac{3}{4} + \frac{1}{2} ) \times 2 \\ \\ = ( \frac{3}{4} + \frac{2}{4} ) \times 2 \\ \\ = \frac{5}{4} \times 2 \\ \\ = \frac{10}{4} = 2 \frac{2}{4} [/tex]