Dalam suata balap mobil seorang pembalap mampu menmpuh jarak 19 km dalam waktu 12 menit berapa kecepatan rsta rata mobil itu
Answer (3)
Equations don't have steepness. "Steepness" is the slope of the line you get when you graph the equation. If you always massage the equation into the form [ y = (something times x) + something }, then the number that multiplies 'x' is the slope of the graph..
y = 15x + 5 The slope is 15.
y = 0.15x - 1 The slope is 0.15 .
y = x The slope is 1. ( y = 1x )
y = x + 100 The slope is 1. ( y = 1x + 100 )
The slopes of the given equations are identified and then ordered from least to greatest. The final order is: y = 0.15 x − 1 , y = x , y = x + 100 , and y = 15 x + 5 . The steepness is then ranked as 1, 2, 3, and 4 based on their values.
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•°• Dalam suatu balap mobil seorang pembalap mampu menempuh jarak 19 km dalam waktu 12 menit. Kecepatan rata-rata mobil tersebut adalah 95 km/jam.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:jarak tempuh = 19 kmwaktu = 12 menit = 0,2 jamKecepatan rata-rata = ?[tex] \: [/tex]Kecepatan = jarak/waktu Kecepatan = 19 km/0,2 jamKecepatan = 95 km/jam[tex] \: [/tex]•°• Jadi, kecepatan rata-rata mobil tersebut adalah 95 km/jam.[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
