3 x 2 − 6 x − 2 = 0 ( 3 x ) 2 − 2 ⋅ 3 x ⋅ 3 + ( 3 ) 2 − ( 3 ) 2 − 2 = 0 ( 3 x − 3 ) 2 − 3 − 2 = 0 ( 3 x − 3 ) 2 = 5 ⟺ 3 x − 3 = − 5 ∨ 3 x − 3 = 5 3 x = 3 − 5 ∨ 3 x = 3 + 5 ∣ m u lt i pl y b o t h s i d es b y 3 3 x = 3 − 15 ∨ 3 x = 3 + 15 ∣ d i v i d e b o t h s i d es b y 3 x = 3 3 − 15 ∨ x = 3 3 + 15
P ro v e : 3 x 2 − 6 x − 2 = 0 a = 3 ; b = − 6 ; c = − 2 Δ = b 2 − 4 a c → Δ = ( − 6 ) 2 − 4 ⋅ 3 ⋅ ( − 2 ) = 36 + 24 = 60 x 1 = 2 a − b − Δ ; x 2 = 2 a − b + Δ Δ = 60 = 4 ⋅ 15 = 4 ⋅ 15 = 2 15 x 1 = 2 ⋅ 3 6 − 2 15 = 3 3 − 15 ∨ x 2 = 2 ⋅ 3 6 + 2 15 = 3 3 + 15
Calculating delta: Δ=b²-4ac a=3 b=-6 c=-2 Δ=36-4 3 (-2)=36+24=60 √Δ=√60 Delta is positive so there are two roots: x1= 2 a − b + 2 d e lt a x1= 2 ∗ 3 6 + d e lt a = 3 3 + 15 x2= 3 3 − 15
To find the roots of the equation 3 x 2 − 6 x − 2 = 0 , we completed the square and found them to be x = 1 + 3 15 and x = 1 − 3 15 . Using the quadratic formula confirmed the same results. Both methods yield the same solutions, demonstrating their consistency in solving quadratic equations.
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•°• Hasil dari 2,25 : 5 adalah 0,45.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:2,25 : 5= 225/100 : 5/1= (225 × 1)/(100 × 5)= 225/500= 45/100= 0,45[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
[tex]2.25 \div 5 \\ = \frac{225}{100} \div \frac{5}{1} \\ \\ = \frac{225}{100} \times \frac{1}{5} \\ \\ = \frac{225}{500} = 0.45[/tex]