Quantity of alcohol =400*15/100 = 60ml x is pure alcohol which must be added : (x + 60)/(x + 400) = 32/100 100x + 6000 = 32x + 12800 => 68x = 6800 => x = 100 100ml pure alcohol must be added
To increase a 400 ml solution of 15% alcohol to a 32% solution, you need to add 100 ml of pure alcohol. This is calculated by determining the amount of alcohol in the original solution and setting up an equation based on the desired concentration. The final solution will then have the required strength of 32%.
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