x 2 − 3 x + 2 = 0 x 2 − x − 2 x + 2 = 0 x ( x − 1 ) − 2 ( x − 1 ) = 0 ( x − 2 ) ( x − 1 ) = 0 x = 2 ∨ x = 1 x 2 − 3 x + 2 = 0 x 2 − 3 x + 4 9 − 4 1 = 0 ( x − 2 3 ) 2 = 4 1 x − 2 3 = 4 1 ∨ x − 2 3 = − 4 1 x − 2 3 = 2 1 ∨ x − 2 3 = − 2 1 x = 2 4 ∨ x = 2 2 x = 2 ∨ x = 1
The quadratic equation x 2 − 3 x + 2 = 0 can be solved by factoring it into ( x − 1 ) ( x − 2 ) = 0 resulting in solutions x = 1 and x = 2 . Additionally, completing the square also confirms these solutions with the final form showing the same results. Both methods effectively demonstrate the two solutions of the equation.
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[tex]3 + 3 \times 3 + 3 \\ = 3 + 9 + 3 \\ = 12 + 3 \\ = 15[/tex]