Apa aksara jawanya semarang

f ( x ) = x 3 − 5 x 2 + 9 x − 5 f ( x ) = x 3 − x 2 − 4 x 2 + 4 x + 5 x − 5 f ( x ) = x 2 ( x − 1 ) − 4 x ( x − 1 ) + 5 ( x − 1 ) f ( x ) = ( x − 1 ) ( x 2 − 4 x + 5 ) ( x − 1 ) ( x 2 − 4 x + 5 ) = 0 x − 1 = 0 x = 1 x 2 − 4 x + 5 = 0 x 2 − 4 x + 4 + 1 = 0 ( x − 2 ) 2 = − 1 x − 2 = i ∨ x − 2 = − i x = 2 + i ∨ x = 2 − i x = { 1 , 2 − i , 2 + i }

Answered by konrad509 | 2024-06-10

The zeros of the function f ( x ) = x 3 − 5 x 2 + 9 x − 5 are x = 1 , x = 2 + i , and x = 2 − i . This consists of one real solution and two complex solutions.
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Answered by konrad509 | 2024-12-24

Jawaban:Terlampir[tex] [/tex]

Answered by ekaarn | 2025-07-09