\left\{\begin{array}{ccc}4x+13y=40\\4x+3y=-40&/\cdot(-1)\end{array}\right\\+\left\{\begin{array}{ccc}4x+13y=40\\-4x-3y=40\end{array}\right\\-----------\\.\ \ \ \ \ \ 10y=80\ \ \ \ /:10\\.\ \ \ \ \ \ y=8\\\\4x+3\cdot8=-40\\4x+24=-40\\4x=-40-24\\4x=-64\ \ \ \ /:4\\x=-16\\\\Solution:x=-16\ and\ y=8.
4x + 13y = 40 4x + 3y = -40 using elimination method 10y = 80 y = 8 substitute y in eq1 4x + 13(8) = 40 4x + 104 = 40 4x = 40 - 104 4x = - 64 x = -16
The solution to the equations is x = − 16 and y = 8 . We found y by eliminating x and then solved for x using substitution. This method effectively demonstrates how to solve a system of linear equations.
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DiketahuiProyek selesai 15 hari dikerjakan 8 orangDitanyaOrang yamg diperlukan jika harua selesai 12 hari.Dijawab8 x 15 = 12 x y120 = 12yy = 120/12y = 10Pekerja yang perlu ditambah= 10 - 8= 2KesimpulanMaka jawabannya 2.