Sebuah kotak berbentuk kubus memiliki panjang sisi 4cm beeapakh volume kubus tersebut
Answer (3)
endpoint: \ ( x_{2},y_{2})= (-4,1) , \\ midpoint : \(x,y)=(-1,3) \\\\Mindpoint \ Formula : \\ (x,y)=\left ( \frac{x_{1}+x_{2} }{2}, \frac{y_ {1}+y_{2} }{2} \right )\\\\(-1,3)=\left ( \frac{x_{1}-4 }{2}, \frac{y_ {1}+1 }{2} \right )
{ 2 x 1 − 4 = − 1 / ⋅ 2 2 y 1 + 1 = 3 / ⋅ 2 { x 1 − 4 = − 2 y 1 + 1 = 6 { x 1 = − 2 + 4 y 1 = 6 − 1 { x 1 = 2 y 1 = 5 A n s w er : seco n d e n d p o in t : ( x 1 , y 1 ) = ( 2 , 5 )
We used the midpoint formula to find the missing endpoint of the line segment. The missing endpoint is the point (2, 5).
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DiketahuiSisi : 4 cmDitanyaV kubusDijawabVolume[tex] = {s}^{3} = {4}^{3} \\ = 4 \times 4 \times 4 \\ = 16 \times 4 \\ = 64[/tex]KesimpulanMaka jawabannya 64cm3.
