Multiples of 3 from 3 to 99 inclusive is a Aritmetic Progression where:
a1 = 3 an = 99 r = 3
Using the formula of general terms:
a n = a 1 + ( n − 1 ) . r 99 = 3 + 3 ( n − 1 ) 99 − 3 = 3 n − 3 3 n = 99 n = 33 Calculating sum:
S 33 = 2 33 ( a 1 + a 33 ) S 33 = 2 33 ( 3 + 99 ) = 2 33 ∗ 102 = 1683
The sum of the multiples of 3 from 3 to 99 inclusive is found to be 1683. This is calculated using the arithmetic sequence formula where the first term is 3, the last term is 99, and there are 33 terms. The total is derived using the sum formula for the first n terms of an arithmetic sequence.
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DiketahuiBerangkat 08.00Sampai 09.20DitanyaLama perjalananDijawab09.2008.00_____ - 01.201 Jam 60 menit= 60 + 20= 80 menitKesimpulanMaka jawabannya 80 menit